4-7
u To generate a sequence of numbers [OPTN]-[LIST]-[Seq]
K1(LIST)5(Seq) <expression> , <variable name> , <start value> , <end value>
, <increment> !/( ) )w
• The result of this operation is stored in ListAns Memory.
Example To input the number sequence 1
2
, 6
2
, 11
2
, into a list, using the function
f(x) = X
2
. Use a starting value of 1, an ending value of 11, and an
increment of 5.
AK1(LIST)5(Seq)
a5(U-Z)4(X)x,4(X)
,b,bb,f!/( ) )w
Specifying an ending value of 12, 13, 14, or 15 produces the same result as shown above
since they are less than the value produced by the next increment (16).
u To find the minimum value in a list [OPTN]-[LIST]-[Min]
K1(LIST)6(g)1(Min)6(g)6(g)1(List) <list number 1 - 26> !/( ) )w
Example To find the minimum value in List 1 (36, 16, 58, 46, 56)
AK1(LIST)6(g)1(Min)
6(g)6(g)1(List)b!/( ) )w
u To find which of two lists contains the greatest value [OPTN]-[LIST]-[Max]
K1(LIST)6(g)2(Max)6(g)6(g)1(List) <list number 1 - 26> ,1(List)
<list number 1 - 26> !/( ) )w
• The two lists must contain the same number of data items. If they don’t, an error occurs.
• The result of this operation is stored in ListAns Memory.
Example To find whether List 1 (75, 16, 98, 46, 56) or List 2 (35, 59, 58, 72, 67)
contains the greatest value
K1(LIST)6(g)2(Max)
6(g)6(g)1(List)b,
1(List)c!/( ) )w
u To calculate the mean of data items [OPTN]-[LIST]-[Mean]
K1(LIST)6(g)3(Mean)6(g)6(g)1(List) <list number 1 - 26> !/( ) )w
Example To calculate the mean of data items in List 1 (36, 16, 58, 46, 56)
AK1(LIST)6(g)3(Mean)
6(g)6(g)1(List)b!/( ) )w
