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INSTRUCTION SET S3C8275X/F8275X/C8278X/F8278X/C8274X/F8274X
6-22
BOR — Bit OR
BOR dst,src.b
BOR dst.b,src
Operation: dst(0) ← dst(0) OR src(b)
or
dst(b) ← dst(b) OR src(0)
The specified bit of the source (or the destination) is logically ORed with bit zero (LSB) of the
destination (or the source). The resulting bit value is stored in the specified bit of the destination.
No other bits of the destination are affected. The source is unaffected.
Flags: C: Unaffected.
Z: Set if the result is "0"; cleared otherwise.
S: Cleared to "0".
V: Undefined.
D: Unaffected.
H: Unaffected.
Format:
Bytes Cycles Opcode
(Hex)
Addr Mode
dst
src
opc
dst | b | 0
src 3 6 07 r0 Rb
opc
src | b | 1
dst 3 6 07 Rb r0
NOTE: In the second byte of the 3-byte instruction formats, the destination (or source) address is four bits,
the bit address 'b' is three bits, and the LSB address value is one bit.
Examples: Given: R1 = 07H and register 01H = 03H:
BOR R1, 01H.1 → R1 = 07H, register 01H = 03H
BOR 01H.2, R1 → Register 01H = 07H, R1 = 07H
In the first example, destination working register R1 contains the value 07H (00000111B) and
source register 01H the value 03H (00000011B). The statement "BOR R1,01H.1" logically ORs
bit one of register 01H (source) with bit zero of R1 (destination). This leaves the same value
(07H) in working register R1.
In the second example, destination register 01H contains the value 03H (00000011B) and the
source working register R1 the value 07H (00000111B). The statement "BOR 01H.2,R1" logically
ORs bit two of register 01H (destination) with bit zero of R1 (source). This leaves the value 07H
in register 01H.