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E. 199.141.27.175
F. 199.141.27.208
Answer: A, C, D
Explanation: When you base your calculations on the network address and the provided subnet mask the valid
host addresses are 199.141.27.33, 199.141.27.119, and 199.141.27.126.
Incorrect Answers:
B, E and F are incorrect; these are not valid host addresses.
Steve McQuerry. Interconnecting Cisco Network Devices. (Cisco Press: 2000) pages 233-236.
Q. 32
The network 172.12.0.0 needs to be divided into subnets where each subnet has the capacity of 458 IP
addresses. What would be the correct subnet mask to accomplish this division keeping the number of
subnets at the maximum.
Type the correct value in each box below.