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[Reference]
Reference
= 5
10
0.005 x 10000 x 1
= 0.25
20
0.0005 x 10000 x 1
D =
... Formula (3)
... Formula (5)
L
∆M x E x R
Then, distance per command pulse (mm) is as follows:
(position resolution)
... Formula (6)
D =
F x 60
N x E
Pr46 = 10000
Pr4A = 0
Pr4B = 2000
Pr46 = 10000
Pr4A = 0
Pr4B = 10000
D =
Pr4B
Pr46 x 2
Motor rotation speed (r/min)
N = F x x 60
E
D
∆M = x x L = x x 20 = 0.002mm
E
D
10000
1
R
1
1
1
D = = 1
500000 x 60
3000 x 10000
0
D =
10000
10000 x 2
Lead of ball screw L = 10mm
Reduction ratio R=1
Position resolution
∆M = 0.005mm
For the encoder of 2500 P/r
(E=10000P/r)
Lead of ball screw L = 20mm
Reduction ratio R=1
Position resolution
∆M = 0.005mm
For the encoder of 2500 P/r
(E=10000P/r)
Lead of ball screw L= 20mm
Reduction ratio R=1
Position resolution
∆M = 0.005mm
Line driver pulse input
500 kpps
For the encoder of 2500 P/r
Pr4A
D =
Pr4B
Pr46 x 2
Pr4A
2000
10000 x 2
0
D =
D =
D =
Example
Example
1
2
N = 500000 x x 60
... Formula (5)
... Formula (3)
20
0.005 x 10000 x 1
D =
= 25
10000
2.5
= 7500
To make motor rotation speed
3000 r/min under the same
condition as above, with lead of
ball screw of L = 20 mm and the
line driver pulse input of 500 kpps.
Command dividing
multiplier ratio
Determine
parameters Pr46,
Pr4A and Pr4B so
that D=5. Consider
the following:
D<1 is not
appropriate to
determination of
the accuracy.
D = 1 is a condition
of minimum
resolution.
Command dividing
multiplier ratio
Thus, motor specification is not met.
Determine
parameters Pr46,
Pr4A and Pr4B so
that D=1. Consider
the following: