Black Box ACR1000A-CTL Network Hardware User Manual


 
Chapter 2: Overview
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Page 11
2.1.5 Active Directory
To streamline administration even further, ServSwitch iPATH supports Active Directory. By synchronizing with an LDAP/Active
Directory server, details of users (including their usernames and group memberships) can be securely synchronized from existing
databases in order to both minimize the initial configuration as well as streamline ongoing updates.
2.1.6 ServSwitch iPATH Interface
ServSwitch iPATH appears in two main ways, depending on whether you are an administrator or a regular user.
• Foradministrators,fullaccesstotheServSwitchiPATHSuiteisgranted.Thiscomprehensiveapplicationshowssixmaintabbed
areas: Dashboard, Channels, Receivers, Transmitters, Users and Presets each of which contains numerous related pages of
settings and options. The Dashboard provides a central location from which the administrator can view overall operation, make
various changes, database backups and also upgrade the firmware of any linked ServSwitch Agility unit.
• Forregularusers,anefficientpagelayoutprovidesalistofallchannelsforwhichyouhavepermissiontovisit.Againsteach
selectable channel name and description, a series of icons provide clear feedback about current availability.
2.1.7 Permissions
Permissions exist between Users, Receivers, and Channels.
By default, all users are granted permission to access ALL receivers.
By default, all receivers have permission to connect to ALL channels.
As shown in the introductory diagram, the missing part is the permission for a user to access each channel.
Permissions between a user and a receiver can be applied in any of the following ways:
• User–>Receiver
• User–>UserGroup–>Receiver
• User–>UserGroup–>ReceiverGroup–>Receiver
• User–>ReceiverGroup–>Receiver
Thus, a very indirect way of granting permissions could be:
• User1isinUserGroup1,
• UserGroup1hasaccesstoChannelGroup1,
• ChannelGroup1containsChannel1,
• Therefore,User1hasaccesstoChannel1indirectly.