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HARSFEN0602
If some function does not return any output by its definition, then zero value as output will be inserted to the
stack actually. Assume that the function foo is declared with no output arguments. So the following
expression:
foo () + 3 is legal, because foo returns zero by default.
Example:
float vec[11], RA[100]; Declare the global variables
float value; Declare the global variable
function [float mean, float std]=statistic(); Prototype of the function
...
[RA[1],RA[2]]=statistic() Calling the STATISTIC function. After
executing RA[1] will be equal to variable
MEAN and RA[2] will be equal to variable
STD
[value]= statistic() In this case, after executing the STATISTIC
function VALUE will be equal to variable
MEAN
…
function [float mean, float std]=statistic() Declaration of a function that calculates mean
and standard deviation of the global vector
vec.
int k; Declare k as automatic variable
global vec[11]; Redeclaration for vec variable (vec is the
global variable that is declared before)
mean=0;
for k = 1:10
mean = mean + vec[k];
end
mean = mean/10; Calculate mean of vec[]
if ( nargout > 1) Only if the standard deviation is asked...
std = 0 ;
for k =1:10
std = std + vec[k] * vec[k] ;
end
st = (1/10)* sqrt( std – 10 * sum)
end
return End of the function body
…
Count of input arguments
The number of input arguments during function call must be the same as it is declared during function
definition.
5.6.4 Automatic variables
A variable declared within a function is automatic. It is generated when the function is
called, and it ceases to exist when the function exits.
At the time of function call, all its automatic variables are set to zero. When the function