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Solving Equations 7–9
File name 32sii-Manual-E-0424
Printed Date : 2003/4/24 Size : 17.7 x 25.2 cm
If H is the height, then the length of the box is (80 – 2H) and the width is (40 –
2H). The volume V is:
V = ( 80 – 2H )
×
(40 – 2H )
×
H
which you can simplify and enter as
V= ( 40 – H )
×
( 20 – H )
×
4
×
H
Type in the equation:
Keys: Display: Description:
{
G
K
V
{
c
#/¾
Selects Equation mode and
starts the equation.
{
\
40
K
H
{
]
#/1.2¾
y
{
\
20
K
H
{
]
.2º1.2¾
y
4
y
K
H
º1.2ºº¾
#/1.2º1
Terminates and displays the
equation.
{
/
)
Checksum and length.
It seems reasonable that either a tall, narrow box or a short, flat box could be
formed having the desired volume. Because the taller box is preferred, larger
initial estimates of the height are reasonable. However, heights greater than
20 cm are not physically possible because the metal sheet is only 40 cm wide.
Initial estimates of 10 and 20 cm are therefore appropriate.
Keys: Display: Description:
Leaves Equation mode.
10
H
H 20
_
Stores lower and upper limit
guesses.