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Let's try some other simple operations before trying the more complicated
expression used earlier for the algebraic operating mode:
Note the position of the y and x in the last two operations. The base in the
exponential operation is y (stack level 2) while the exponent is x (stack
level 1) before the key
Q is pressed. Similarly, in the cubic root
operation, y (stack level 2) is the quantity under the root sign, and x (stack
level 1) is the root.
Try the following exercise involving 3 factors: (5 + 3) × 2
Let's try now the expression proposed earlier:
123/32 123`32/
4
2
4`2Q
3
√(√27)
27R3@»
5`3+ Calculates (5 +3) first.
2X Completes the calculation.
3` Enter 3 in level 1
5` Enter 5 in level 1, 3 moves to level 2
3` Enter 3 in level 1, 5 moves to level 2, 3 to level 3
3* Place 3 and multiply, 9 appears in level 1
Y 1/(3
×3), last value in lev. 1; 5 in level 2; 3 in level 3
- 5 - 1/(3
×3) , occupies level 1 now; 3 in level 2
* 3
× (5 - 1/(3×3)), occupies level 1 now.
23`Enter 23 in level 1, 14.66666 moves to level 2.
3Q
Enter 3, calculate 23
3
into level 1. 14.666 in lev. 2.
/
(3
× (5-1/(3×3)))/23
3
into level 1
2.5Enter 2.5 level 1
!¸
e
2.5
, goes into level 1, level 2 shows previous value.
5.2
3
23
33
1
53
e+
⋅
−⋅
⎟
⎠
⎞
⎜
⎝
⎛
SG49A.book Page 9 Friday, September 16, 2005 1:31 PM