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20090601
When the two population standard deviations are equal (pooled)
When the two population standard deviations are not equal (not pooled)
Definition of Terms
C-Level : confidence level (0
C-Level < 1)
List(1) : list where sample 1 data is located
List(2) : list where sample 2 data is located
Freq(1) : frequency of sample 1 (1 or list name)
Freq(2) : frequency of sample 2 (1 or list name)
Pooled : On or Off
M
1
: sample mean of sample 1 data
s
x
1
: sample standard deviation of sample 1 (s
x
1
0)
n
1
: size of sample 1 (positive integer)
M
2
: sample mean of sample 2 data
s
x
2
: sample standard deviation of sample 2 (s
x
2
0)
n
2
: size of sample 2 (positive integer)
Calculation Result Output
Lower : interval lower limit (left edge)
Upper : interval upper limit (right edge)
df
: degrees of freedom
M
1
: sample mean of sample 1 data
M
2
: sample mean of sample 2 data
s
x
1
: sample standard deviation of sample 1
s
x
2
: sample standard deviation of sample 2
s
p
: pooled sample standard deviation (Displayed only when pooling is
turned on.)
n
1
: size of sample 1
n
2
: size of sample 2
Lower = (o
1
– o
2
)– t
2
n
1
+n
2
–2
sp
2
n
1
1
+
n
2
1
Upper = (o
1
– o
2
)+ t
2
s
p
2
n
1
+n
2
–2
n
1
1
+
n
2
1
Lower = (o
1
– o
2
)– t
2
n
1
+n
2
–2
sp
2
n
1
1
+
n
2
1
Upper = (o
1
– o
2
)+ t
2
s
p
2
n
1
+n
2
–2
n
1
1
+
n
2
1
Lower = (o
1
– o
2
)– t
df
2
+
n
1
s
x
1
2
n
2
s
x
2
2
Upper = (o
1
– o
2
)+ t
df
2
+
n
1
s
x
1
2
n
2
s
x
2
2
Lower = (o
1
– o
2
)– t
df
2
+
n
1
s
x
1
2
n
2
s
x
2
2
Upper = (o
1
– o
2
)+ t
df
2
+
n
1
s
x
1
2
n
2
s
x
2
2
C =
df =
1
C
2
n
1
–1
+
(1–C)
2
n
2
–1
+
n
1
n
1
n
2
s
x1
2
s
x1
2
s
x2
2
C =
df =
1
C
2
n
1
–1
+
(1–C)
2
n
2
–1
+
n
1
n
1
n
2
s
x1
2
s
x1
2
s
x2
2
7-10-9
Confidence Intervals