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We find two critical points, one at x = 11/3 and one at x = -1. To evaluate the
second derivative at each point use:
The last screen shows that f”(11/3) = 14, thus, x = 11/3 is a relative minimum.
For x = -1, we have the following:
This result indicates that f”(-1) = -14, thus, x = -1 is a relative maximum.
Evaluate the function at those points to verify that indeed f(-1) > f(11/3).
Higher order derivatives
Higher order derivatives can be calculated by applying a derivative function
several times, e.g.,